Number of points where f(x)=cos|x|+|sinx| is not differentiable in x∈(0,4π), is:
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Solution
For x∈(0,4π), |x|=x⇒f(x)=cosx+|sinx|
Now, cosx is continuous and differentiable everywhere for x∈(0,4π), but |sinx| is non differentiable for x=π,2π,3π because at these points, it has sharp corners.
So, f(x) is not differentiable at 3 points.