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Question

Number of points where f(x)=xsgn(1x2) is non-differentiable is

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Solution

To find: Number of points where f(x)=|x.sgn(1x2)| is non- differentiable
For x(1,1)(1x2)>0sgn(1x2)=1
For x=(1,1)(1x2)=0sgn(1x2)=0
For x(,1)(1,)(1x2)<0sgn(1x2)=1
f(x)=|x|;x(1,1)0;x(1,1)|x|=|x|;x(,1)(1,)
Hence, f(x)=|x| with discontinuity at x=1,&1
Total points of non-differentiability =3

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