CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Number of points where f(x)=xsgn(1x2) is non-differentiable is

Open in App
Solution

To find: Number of points where f(x)=|x.sgn(1x2)| is non- differentiable
For x(1,1)(1x2)>0sgn(1x2)=1
For x=(1,1)(1x2)=0sgn(1x2)=0
For x(,1)(1,)(1x2)<0sgn(1x2)=1
f(x)=|x|;x(1,1)0;x(1,1)|x|=|x|;x(,1)(1,)
Hence, f(x)=|x| with discontinuity at x=1,&1
Total points of non-differentiability =3

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Theorems for Differentiability
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon