Question

Number of positive integral solution of $xyz=30$ is

• A. $9$
• B. $27$
• C. $81$
• D. $243$

Answer 1

The correct option is B $27$

$\begin{array}{c}30=1\times 5\times 6or30=1\times 2\times 15or\\ 30=1\times 3\times 10or30=2\times 3\times 5or\\ 30=1\times 1\times 30\\ \therefore x,y,zcanbetakethevaluefromanyoftheabovetriplets.\\ i.e.3!or3!or3!or3!or\frac{3!}{2!}\\ thenumberofsolution=6+6+6+6+3=27\end{array}$

Hence,

option $B$ is correct answer