1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XIII
Mathematics
Multinomial Theorem
Number of pos...
Question
Number of positive integral solutions of
15
<
x
1
+
x
2
+
x
3
≤
20
is
Open in App
Solution
15
<
x
1
+
x
2
+
x
3
≤
20
⇒
x
1
+
x
2
+
x
3
=
16
+
r
r
=
0
,
1
,
2
,
3
,
4
Now number of positive integral solution of
⇒
x
1
+
x
2
+
x
3
=
16
+
r
is
16
+
r
−
1
C
3
−
1
=
15
+
r
C
2
Thus required number of solutions
=
4
∑
r
=
0
15
+
r
C
2
=
15
C
2
+
16
C
2
+
17
C
2
+
18
C
2
+
19
C
2
=
685
Suggest Corrections
0
Similar questions
Q.
Number of positive integral solutions of
15
<
x
1
+
x
2
+
x
3
≤
20
is
Q.
Total number of positive integral solutions of
15
<
x
1
+
x
2
+
x
3
≤
20
is
Q.
The total number of positive integral solution of
15
<
x
1
+
x
2
+
x
3
≤
20
is equal to
Q.
The number of non-negative integral solutions of
x
1
+
x
2
+
…
+
x
10
≤
15
is
Q.
Number of non negative integral solutions of
x
1
+
x
2
+
x
3
+
x
4
=
20
.
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Explore more
Multinomial Theorem
Standard XIII Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app