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Question

Number of positive integral solutions of 15<x1+x2+x320 is

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Solution

15<x1+x2+x320
x1+x2+x3=16+r
r=0,1,2,3,4
Now number of positive integral solution of
x1+x2+x3=16+r is
16+r1C31= 15+rC2

Thus required number of solutions =4r=0 15+rC2= 15C2+ 16C2+ 17C2+ 18C2+ 19C2=685

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