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Byju's Answer
Standard XI
Mathematics
Range of Quadratic Expression
Number of pos...
Question
Number of positive integral value of '
p
' for which the equation
p
.2
e
x
+
e
−
x
−
8.2
e
x
+
e
−
x
2
+
p
=
0
has atleast one solution is
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Solution
2
e
x
+
e
−
x
2
=
t
≥
2
So,
p
t
2
−
8
t
+
p
=
0
t
+
1
t
=
8
p
Minimum value of
t
+
1
t
is
5
2
⇒
8
p
≥
5
2
⇒
p
≤
16
5
p
=
1
,
2
,
3
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Standard XI Mathematics
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