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Byju's Answer
Standard XII
Mathematics
Proof of Intermediate Value Theorem
Number of pos...
Question
Number of positive roots of
x
4
+
3
x
3
−
2
x
2
−
3
=
0
is
A
zero
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B
2
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C
1
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D
3
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Solution
The correct option is
C
1
x
4
+
3
x
3
−
2
x
2
−
3
=
0
f
(
x
)
=
x
4
+
3
x
3
−
2
x
2
−
3
+ + - -
Maximum number of positive roots (sign change) =1
f
(
0
)
=
−
3
f
(
2
)
=
29
SIgn is changing b/w (0,2) and only 1 positive root is possible.
∴
This function will have only 1 positive root.
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0
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