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Question

Number of positive roots of x5+2x3−5x2+1=0 is

A
zero
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B
atmost 1
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C
atmost 2
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D
3
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Solution

The correct option is B atmost 2
x5+2x35x2+1=0
f(x)=
x5+2x35x2+1
+ + - +
Maximum number of positive roots =2

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