Number of real solution of |x−3|=√x−1 which are not prime
A
2
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B
3
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C
1
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D
0
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Solution
The correct option is D0 |x−3|=√x−1 ∵|x−3|≥0 and √x−1≥0 Since both the sides are always ≥0 So, by squaring both the sides, we get ⇒|x−3|2=(√x−1)2 ⇒x2+9−6x=x−1 ⇒x2−7x+10=0 ⇒(x−5)(x−2)=0 ⇒x=2,5