Question

Number of red roses sold on a flower shop per day is given by the inequality 2x + 11 > 3x - 21. Which of the following can be the number of red roses sold on a day?

• A. 50
• B. 45
• C. 40
• D. 20

Answer 1

The correct option is D 20

Given inequation is 2x + 11 > 3x - 21

For the first option:
Substituting x = 20, we see:

$LHS=2x+11=2\times 20+11=51$
$RHS=3x-21=3\times 20-21=39$

∴ LHS > RHS

So, number of red roses sold can be 20.

For the second option:
Substituting y = 40, we see:

$LHS=2x+11=2\times 40+11=91$
$RHS=3x-21=3\times 40-21=99$
∴ LHS < RHS

So, 40 roses can't be sold on a day.

For the third option:
Substituting y = 45, we see:

$LHS=2x+11=2\times 45+11=101$
$RHS=3x-21=3\times 45-21=114$
∴ LHS < RHS

So, 45 roses can't be sold on a day.

For the last option:
Substituting y = 50, we see:
$LHS=2x+11=2\times 50+11=111$
$RHS=3x-21=3\times 50-21=129$

∴ LHS < RHS

So, 50 roses can't be sold on a day.

∴ The number of roses sold on the day = 20