Question

Number of roots of the quadratic equation $8{\sec }^{2}x-6\sec x+1=0$ is/are:

Answer 1

On solving, $\sec x=\frac{1}{2}or\frac{1}{4}$
$\Rightarrow \cos x=2$ or 4
Both the values are not possible.
Hence there exist no solution of given equation.