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B
4σ and 2π
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C
4σ and 3π
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D
3σ and 2π
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Solution
The correct option is D4σ and 3π ClO−4has 4 bond pairs and zero lone pairs. Hence, it requires 4 orbitals. The hybridization is sp3. Shape is tetrahedral. ClO−4 clearly has 3π bonds and 4 sigma bonds.