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Question

Number of six digit numbers which have 3 digits even and 3 digits odd , if each digit is to be used atmost once is

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Solution

Dear student
number of ways of selection of 3 even number from 0,2,4,6,8 is 5C3

number of ways of selection of 3 odd number from 1,3,5,7,9 is 5C3

Total ways =5C35C3 6!

but this number also include zero at first place

total number in which zero at place place = 5C34C2 5!

so total number =5C35C3 6! -5C34C2 5!
Regards


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