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Question

Number of solution of the equation |sinx|=sinx+2cosx in the interval [0,2π] is

A
One
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B
Two
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C
Three
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D
Four
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Solution

The correct option is B Two
|sinx|=sinx+2cosx will hold true when 2cosx=0

So, the solution is x=π2,3π2

Hence, number of solution is 2

Therefore, Answer is 2

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