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Question

Number of solution of the equation |sin x | = sin x + 2 cos x , in the interval [0,2π]

A
One
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B
Two
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C
Three
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D
Four
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Solution

The correct option is B Two
|sinx|=sinx+2cosx
When sinx>0 or 0x<π
The equation is, sinx=sinx+2cosx
cosx=0
x=π2
When, sinx<0 or π<x2π
The equation is, sinx=sinx+2cosx
2sinx=2cosx
tanx=1
tanx=tan7pi8
x=7π8
Thus, there are two solutions.

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