Number of solution of the equation |sin x | = sin x + 2 cos x , in the interval [0,2π]
A
One
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B
Two
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C
Three
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D
Four
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Solution
The correct option is B Two |sinx|=sinx+2cosx When sinx>0 or 0≥x<π The equation is, sinx=sinx+2cosx cosx=0 x=π2 When, sinx<0 or π<x≤2π The equation is, −sinx=sinx+2cosx −2sinx=2cosx tanx=−1 tanx=tan7pi8 x=7π8 Thus, there are two solutions.