The correct option is A 0
|x−1|−|x−2|=10
Critical points are x=1,2
Case-1: x≤1
⇒−(x−1)−(−(x−2))=10⇒−x+1+x−2=10
⇒−1=10 (not possible)
Case-2: 1<x<2
⇒(x−1)−(−(x−2))=10⇒x−1+x−2=10
⇒x=132∉(1,2)
Case-3: x≥2
⇒(x−1)−(x−2)=10
⇒1=10 (not possible)
So the equation has no solution.