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Byju's Answer
Standard XII
Mathematics
Range
Number of sol...
Question
Number of solution(s) of the equation
2
cos
2
θ
−
3
√
2
cos
θ
+
2
=
0
in
(
0
,
10
)
is
Open in App
Solution
2
cos
2
θ
−
3
√
2
cos
θ
+
2
=
0
⇒
(
2
cos
θ
−
√
2
)
(
cos
θ
−
√
2
)
=
0
⇒
cos
θ
=
1
√
2
or
cos
θ
=
√
2
(rejected)
⇒
cos
θ
=
1
√
2
If
θ
∈
(
0
,
10
)
,
then
θ
=
{
π
4
,
7
π
4
,
9
π
4
}
∴
Number of solutions is
3.
Suggest Corrections
0
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