Number of solutions for 2sin|x|=4|cosx| in [−π,π] is equal to
A
2
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B
4
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C
6
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D
8
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Solution
The correct option is B4 y=4|cosx| and y=2sin|x| ∴2|cosx|=sin|x| The total number of solutions for the given equation is equal to the number of points of intersection of curves y=2|cosx| and y=sin|x|.
Clearly, the two curves intersect at four points. So, there are four solutions of the given equation.