Number of solutions for the line 4x-Ay = 0 where HCF(A,4) = 1 and 0

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Solution

The correct option is B
1

y = ( $\frac{4}{A}$ )x where HCF (A,4) =1 , therefore x has to be a multiple of A because x and y are integers. There are 45 solutions . Therefore A has to be 11.

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Number of solutions for the line 4x-Ay = 0 where HCF(A,4) = 1 and 0

The correct option is B 1 y = ( 4A)x where HCF (A,4) =1 , therefore x has to be a multiple of A because x and y are integers. There are 45 solutions . Therefore A has to be 11.

The correct option is B
1

y = ( $\frac{4}{A}$ )x where HCF (A,4) =1 , therefore x has to be a multiple of A because x and y are integers. There are 45 solutions . Therefore A has to be 11.