Number of solutions for the system of equations $3 x + 4 y + 2 z = 1, 3 x + 2 y + 4 z = 4$ and $6 x + 8 y + 4 z = 3$

0

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Solution

The correct option is A $0$
Given System of equations are
$3 x + 4 y + 2 z = 1 \dots (i)$
$3 x + 2 y + 4 z = 4 \dots (i i)$ and
$6 x + 8 y + 4 z = 3 \dots (i i i)$
Taking $2$ common from $(i i i),$ we get $3 x + 4 + 2 z = \frac{3}{2}$
Now comparing with equation $(i)$
These two planes are parallel.
$∴$ They never intersect and don't have any common solution.

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