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Question

Number of solutions of the equation |cos3θ|=1 in [π,π] is

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Solution

|cos3θ|=1
cos3θ=±1

When cos3θ=1
3θ=2nπ, nZ
θ=nπ3, nZ
Number of solutions in [π,π] are 3.
i.e. {2π3,0,2π3}

When cos3θ=1
3θ=(2n+1)π, nZ
θ=(2n+13)π, nZ
Number of solutions in [π,π] are 4.
i.e. {π,π3,π3,π}

Hence, total number of solutions =7

Alternate Solution:
|cosθ| is periodic function with period of π
Hence period of |cos3θ| is π3

Number of solution in (0,π/3]is 1
So number of solution in (0,π] is 3
similarly no of solution [π,0) is 3
here, θ=0 is also a solution
total number of solution is 7

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