Question

Number of solutions of the equation $[y+\left[y\right]]=2$ = 2 cosx is not equal to, where $y=\frac{1}{3}[sinx+[sinx+\left[sinx\right]\left]\right]$ and [.] denotes the greatest integer function

• A. 1
• B. 0
• C. 2
• D. 3

Answer 1

Answer: (A), (C), (D)

The correct options are
A

1

C

2

D

3

[y+[y]]= 2 cos $x\Rightarrow \left[y\right]$ = cos x and and $y=\frac{3}{3}\left[sinx\right]=\left[sinx\right]$
[sin x]=cos x
Number of solution in $[0,2\pi ]$ is 0.
Total solution = 0.