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Question

Number of solutions of the equation sin1(1x)2sin1x=π2 is

A
1
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B
2
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C
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Solution

The correct option is A 1
Let x = sin y
sin1(1sin y)2 sin1(sin y)=π2
sin1(1siny)=π2+2y
1sin y=cos 2y
1cos 2y=sin y2 sin2ysin y=0
sin y=0 (or) sin y=12
x=0 (or) x=12
But x=12 is pseudo result
x = 0 is the only solution

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