Number of solutions of the equations $x + 2 y + z = 1, 3 x + 6 y + 3 z = 3$ is

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Infinity

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Solution

The correct option is D Infinity
Consider the first equation
$x + 2 y + z = 1$
Multiplying the entire equation by 3 give us
$3 x + 6 y + 3 z = 3$
Therefore both the equations form a coincident system of equation.
Hence the above system of equations have infinite number of solutions.

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