Number of $s p^{3}$ hybridised atom in borax $N a_{2} B_{4} O_{7}, 10 H_{2} O$ is $x$ . Find the value of $\frac{x}{19}$

Open in App

Solution

$(N a_{2} B_{4} O_{7} . 10 H_{2} O)$
is actually $N a_{2} [B_{4} O_{5} (O H)_{4}] . 8 H_{2} O$
Anionic part of borax $\Rightarrow [B_{4} O_{5} (O H)_{4}]^{2 -}$

In the anionic part,
Number of $s p^{3}$ hybridized atom = 11 [2 boron + 9 oxygen]
Number of $s p^{2}$ hybridized atom = 2[2 boron]
Also, $8 H_{2} O$ has $8 s p^{3}$ hybridized atoms.
So, total $s p^{3}$ hybridised atoms $= 11 + 8 = 19$
$x = 19$
$∴ \frac{x}{19} = \frac{19}{19} = 1$

Suggest Corrections

Similar questions

Q. Number of

s p^{3}

hybridised atom in borax

N a_{2} B_{4} O_{7}, 10 H_{2} O

x

. Find the value of

\frac{x}{19}

The number of $s p^{3}$ hybridised boron atoms in borax are

The number of $s p^{2}$ hybridised boron atoms in borax are

In the tetranuclear unit of borax $[B_{4} O_{5} (O H)_{4}]^{2 -}$ , the number of B – O – B bridges formed between $s p^{3}$ boron & $s p^{2}$ boron is ‘x’ and the number B-O-B bridges formed between $s p^{3}$ boron & $s p^{3}$ boron is ‘y’.
Then (x – y) is___

Q. Which of the following underlined atoms in oxyacids have

s p^{3}

hybridised atoms ?

Join BYJU'S Learning Program

Number of sp3 hybridised atom in borax Na2B4O7,10H2O is x. Find the value of x19

Number of $s p^{3}$ hybridised atom in borax $N a_{2} B_{4} O_{7}, 10 H_{2} O$ is $x$ . Find the value of $\frac{x}{19}$