Number of sp3 hybridised atom in borax Na2B4O7,10H2O is x. Find the value of x19
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Solution
(Na2B4O7.10H2O)
is actually Na2[B4O5(OH)4].8H2O
Anionic part of borax ⇒[B4O5(OH)4]2−
In the anionic part,
Number of sp3 hybridized atom = 11 [2 boron + 9 oxygen]
Number of sp2 hybridized atom = 2[2 boron]
Also, 8H2O has 8sp3 hybridized atoms.
So, total sp3 hybridised atoms =11+8=19 x=19 ∴x19=1919=1