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Question

Number of sp3 hybridised atom in borax Na2B4O7,10H2O is x. Find the value of x19

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Solution

(Na2B4O7.10H2O)
is actually Na2[B4O5(OH)4].8H2O
Anionic part of borax [B4O5(OH)4]2


In the anionic part,
Number of sp3 hybridized atom = 11 [2 boron + 9 oxygen]
Number of sp2 hybridized atom = 2[2 boron]
Also, 8H2O has 8 sp3 hybridized atoms.
So, total sp3 hybridised atoms =11+8=19
x=19
x19=1919=1

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