Question

Number of sp³ carbon atoms, pi bonds and sigma bonds in enol form of acetophenone respectively

Answer 1

Acetophenone

1. Acetophenone is an organic chemical with the formula ${\mathrm{C}}_6{\mathrm{H}}_5\mathrm{C}\left(\mathrm{O}\right){\mathrm{CH}}_3$ and it's the most basic aromatic ketone.
2. The enol form is an organic compound that contains a Hydroxyl group bonded to a carbon atom having a double bond and that is usually characterized as$(\mathrm{C}=\mathrm{C}(\mathrm{OH})$. The enol form of acetophenone is $2-$Phenylethenol.
3. Structure:

4. In this Enol form of acetophenone there are no ${\mathrm{sp}}^3$ hybridized carbons, $4$ pi bonds, and $15$ sigma bonds.

Therefore, the number of ${\mathrm{sp}}^3$ hybridized carbons, pi bonds, and sigma bonds are 0,4 and 15.