Number of straight lines which satisfy the different equation dydx+x(dydx)2−y=0 is-
Let y=mx+c of a solution of given D.E.
Then dydx=m
So m+xm2−(mx+c)=0
⇒m+(m2+m)n+c=0
⇒m2−m=0;m+c=0
⇒m(m−1)=0
m=0 or 1
Of m=0,c=0;m=1,c=+1
Lines are y=0andy=x+c
y=x+1
Two lines are possible