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Question

Number of terms in the expansion of [(x+1x)2(x1x)2]1007 is ...

A
2013
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B
2014
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C
1
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D
2008
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Solution

The correct option is C 1
[(x+1x)2(x+1x)2]1007
[x2+1x2+2(x2+1x22)]1007
(x2+1x2x21x2+2+2)1007
x2+1x241007
x2+1x2 No. of term :1 Option C is correct


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A+B+C=N (N Fixed)
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