$Number of terms in the expansion of {(x_{1} + x_{2} + x_{3} + . . . + x_{r})}^{n} is equal to n + r - 1 C r - 1$

False

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True

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Solution

The correct option is B True

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Similar questions

Find the number of terms in the expansion of $(x_{1} + x_{2} + x_{3} . . . . x_{k})^{n}$

{(x^{3} + 1 + \frac{1}{x^{3}})}^{n}; x \in R^{+}

n \in N

x_{1}, x_{2}, x_{3}

x^{3} - 6 x^{2} + 3 p x - 2 p = 0 (p \in R)

{sin}^{- 1} (\frac{1}{x_{1}} + \frac{1}{x_{2}}) + {cos}^{- 1} (\frac{1}{x_{2}} + \frac{1}{x_{3}}) - {tan}^{- 1} (\frac{1}{x_{3}} + \frac{1}{x_{1}})

{⎛ ⎜ ⎜ ⎜ ⎝ \frac{x + 1}{x^{\frac{2}{3}} - x^{\frac{1}{3}} + 1} \frac{x - 1}{x - x^{\frac{1}{2}}} ⎞ ⎟ ⎟ ⎟ ⎠}^{10}

x

(x_{1} + x_{2} + . . . . . . x_{10})^{5}

^{14} C_{5}

^{n + r - 1} C_{n}

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