Question

Number of the geometrical isomers for the molecule are:

• A. 2
• B. 4
• C. 6
• D. 8

Answer 1

The correct option is C 6

3 double bonds and the molecule is symmetric n = 3
So, total geometrical isomers $=2^{n-1}+2^{\frac{n-1}{2}}=2^{3-1}+2^{\frac{3-1}{2}}=2^2+2^1=4+2=6$