Question

Number of turns in the primary coil of a transformer is 200 and that in secondary coil is 500. If the voltage across primary is 50V at 60Hz frequency and load resistance across secondary coil is $100\Omega$, then current in secondary coil is

• A. 0.5A
• B. 1.25 A
• C. 1.5 A
• D. 0.75 A

Answer 1

The correct option is B 1.25 A

$\frac{V_P}{V_S}=\frac{N_P}{N_S}\Rightarrow \frac{50}{V_S}=\frac{200}{500}\Rightarrow V_S=\frac{50\times 500}{200}$
$V_S=I_{S}R\Rightarrow \frac{50\times 500}{200}=I_S\times 100$
$I_S=1.25A$