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Byju's Answer
Standard XII
Mathematics
Direction Ratios
Number of uni...
Question
Number of unimodular complex number which satisfies the locus
a
r
g
(
z
−
1
z
+
i
)
=
π
2
A
0
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B
1
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C
2
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D
3
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Solution
The correct option is
A
0
Solution:- (A) 0
a
r
g
(
z
−
1
z
+
i
)
=
π
2
Line segment joining '
1
' and '
−
i
' subtends right angle at varia]ble point
P
(
z
)
.
Locus of point
P
(
z
)
is
C
1
as shown in the attached figure.
Now, unimodular complex numbers lie on the circle
C
2
with centre at the origin, i.e.,
(
0
,
0
)
and radius
1
.
Clearly,
1
and
−
i
are the two possible points but these points are not satisfying equation
(
1
)
Hence no such complex number exist.
Hence the required answer is (A) 0.
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