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Question

Number of unimodular complex number which satisfies the locus arg(z1z+i)=π2

A
0
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B
1
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C
2
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D
3
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Solution

The correct option is A 0
Solution:- (A) 0
arg(z1z+i)=π2
Line segment joining '1' and 'i' subtends right angle at varia]ble point P(z).
Locus of point P(z) is C1 as shown in the attached figure.
Now, unimodular complex numbers lie on the circle C2 with centre at the origin, i.e., (0,0) and radius 1.
Clearly, 1 and i are the two possible points but these points are not satisfying equation (1)
Hence no such complex number exist.
Hence the required answer is (A) 0.

1045593_1063988_ans_aaa8cb941fff44ba9b4b9c0d6ab56a3a.jpg

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