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Byju's Answer
Standard XII
Mathematics
Absolute Value Function
Number of val...
Question
Number of value(s) of
x
satisfying the equation
−
2
|
x
−
14
|
+
5
=
−
6
|
x
−
15
|
−
1
is
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Solution
−
2
|
x
−
14
|
+
5
=
−
6
|
x
−
15
|
−
1
⇒
3
|
x
−
15
|
−
|
x
−
14
|
+
3
=
0
If
x
≥
15
,
3
x
−
45
−
x
+
14
+
3
=
0
⇒
2
x
=
28
⇒
x
=
14
If
14
≤
x
<
15
,
−
3
x
+
45
−
x
+
14
+
3
=
0
⇒
4
x
=
62
⇒
x
=
15.5
If
x
<
14
,
−
3
x
+
45
+
x
−
14
+
3
=
0
⇒
2
x
=
34
⇒
x
=
17
Hence, there is no value of
x
satisfying the given equation.
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Absolute Value Function
Standard XII Mathematics
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