CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Number of values of x, satisfying the equation (x+8)+2(x+7)+(x+1)x+7=4, is

A
0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 1
(x+7+1)+(x+1)x+7=4
(x+1)x+7=3x+7
(x+1)x+7=9+(x+7)6x+7
5x+7=15
x+7=9x=2
Only one value of x will satisfy the equation.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Real Valued Functions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon