Question

Number of ways in which $3$ persons throw a normal die to have a total score of $11$ is:

• A. $27$
• B. $25$
• C. $29$
• D. $18$

Answer 1

The correct option is A $27$

$\bullet$ If person$1$ gets a $1$ , the q$2$person$2$ and$3$ need a combination$10$, which can be done in $3$ ways

$\bullet$ Of person $1$ gets a $2$, the person $2$and $3$ need a combination$9$, which can be done in $4$ ways

$\bullet$ Of person 1 gets a $3$, the person$2$and$3$needs a combinations $8$ , which can be done ion $5$ ways

$\bullet$ If person $1$ gets $4$, then $6$ ways

similarly if he gets 5, then it can be done in $5$ ways

$\bullet$ For person $1$gets a $6$, then it can be done in$4$ ways

$\therefore$ Total = $27$ ways to get $11$.