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Question

Number of ways in which an ordered set of r whole numbers (r2) can be selected that their sum is n is equal to

A
n+r1Cn
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B
n+1Cr+1
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C
n+r1Cr
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D
None of these
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Solution

The correct option is B n+r1Cn
Consider the sum n as n identical objects
Now consider that all the n objects are placed on a row.
Let us assume some separators that separates the n objects.
Now as we want to separate them into r group[as blank groups are also allowed],take the separators as objects.
Now we need r1 separators to make r groups.Therefore total number of objects is n+r1.
There will be (r1) places for the separators to occupy.
Therefore we can arrange the separators in n+r1Cr1ways

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