Number of ways in which an ordered set of r whole numbers (r≥2) can be selected that their sum is n is equal to
A
n+r−1Cn
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B
n+1Cr+1
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C
n+r−1Cr
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D
None of these
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Solution
The correct option is Bn+r−1Cn Consider the sum n as n identical objects Now consider that all the n objects are placed on a row. Let us assume some separators that separates the n objects.
Now as we want to separate them into r group[as blank groups are also allowed],take the separators as objects. Now we need r−1 separators to make r groups.Therefore total number of objects is n+r−1.
There will be (r−1) places for the separators to occupy.
Therefore we can arrange the separators in n+r−1Cr−1ways