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Question

Number of ways of selecting one or more things from p identical things of one type, q identical things of one type and r identical things of one type and n different things is given by

A
pqrn1
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B
2npqr1
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C
(p+1)(q+1)(r+1)2n1
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D
none of these
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Solution

The correct option is C (p+1)(q+1)(r+1)2n−1p⟶one typeq⟶one typer⟶one typen⟶diffrent Number of selecting zero or more things of(a) p idntical things p+1(b) q idntical things =q+1(c) r idntical things =r+1Number of ways of selecting n diffrent things =(2)nNumber of ways of selecting zero things =1Total number of ways =(p+1)(q+1)(r+1)2n−1

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