Question

Numbers $1$ to $5$ are written on separate slips, one number on one slip and put in a box. Wahida pick a slip from the box without looking at it. What is the probability that the slip bears an odd number?

• A. $\frac{1}{5}$
• B. $\frac{2}{5}$
• C. $\frac{3}{5}$
• D. $\frac{4}{5}$

Answer 1

The correct option is C

$\frac{3}{5}$

Total number of slips in the box $=5$

Number of slip picked by Wahida from the box $=\left\{1,3,5\right\}=3$ ( As Wahida picks an odd number)

We know that,

$ProbabilityofoccuringaneventP\left(E\right)=\frac{Numberoffavourableoutcome}{Totalnumberofpossibleoutcome}=\frac{n\left(E\right)}{n\left(S\right)}$

Total number of possible outcomes $=$ Total number of slips in the box $=n\left(S\right)=5$

Total number of favorable outcomes $=$Number of slip picked by Wahida from the box $=n\left(E\right)=3$

Therefore,

Probability that the slip bears an odd number $=$ $=\frac{Numberoffavorableoutcome}{Totalnumberofoutcome}=\frac{n\left(E\right)}{n\left(S\right)}=\frac{3}{5}$

Hence, Probability that the slip bears an odd number is $\frac{3}{5}$.