Numbers of compounds having linear shape
$N H_{3}, H_{2} S, C O_{2}, I_{3}^{-}, X e F_{2}, B e C l_{2}, I C l_{2}^{+}, X e F_{4}, X e O_{4}, C_{3} O_{2}$

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Solution

$C O_{2}, X e F_{2}, B e C l_{2}, C_{3} O_{2}$ all have linear shape with $180^{o}$ band angle $N H_{3}$ has hyramidal, $H_{2} S$ has bent, $I_{3}^{+}$ and $I C l_{2}^{+}$ have trigenal biphanidal, $X e F_{4}$ has square planar shape.

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B e C l_{2}, X e F_{2}, N H_{3}, P C l_{3} F_{2}, P C l_{2} F_{3}, B C l_{3}, S F_{6}, X e F_{4}

I_{3}^{-}, X e F_{2}, X e F_{4}, H_{2} O, N H_{2}^{-} H_{2} S, H_{2} S O_{4}, N F_{3}

I_{3}^{+}, X e F_{2}, X e F_{4}, H_{2} O, N H_{2}^{-}, H_{2} S, H_{2} S O_{4}, N F_{3}

S O_{2}, C O_{2}, N_{2} O, O F_{2}, {I C l_{2}}^{-}, {I_{3}}^{-}, N O_{2}, {N O_{2}}^{-}, {N O_{2}}^{+}, {B F_{2}}^{-}, B e C l_{2}, {N_{3}}^{-}, H C N .

B e C l_{2}, N_{3}^{-}, N_{2} O, N O_{2}^{+}, O_{3}, S C l_{2}, I C l_{2}^{-}, I_{3}^{-}

X e F_{2}

S = 16, C l = 17, I = 53

X e = 54