NX is produced by the following set of reactions- M - X2 - MX2 3MX2 - X2 - M3 X8 M3 X8 - Na2CO3 - NX - CO2 - M3O4How much M metal is consumed to produce 206 gm of NX- -Take atomic wt- of M - 56- N - 23- X - 80-

The correct option is D 42 gm #160;42 gm of #160;M (metal) is consumed to produce 206 gm of NX.Hence, the correct option is A ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Law of Mass Action

NX is produce...

Question

NX is produced by the following set of reactions.

$M + X_{2} \to M X_{2}$
$3 M X_{2} + X_{2} \to M_{3} X_{8}$
$M_{3} X_{8} + N a_{2} C O_{3} \to N X + C O_{2} + M_{3} O_{4}$
How much M (metal) is consumed to produce 206 gm of NX?
[Take atomic wt. of M = 56, N = 23, X = 80]

42

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

56

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{14}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{7}{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $42$ gm
42 gm of M (metal) is consumed to produce 206 gm of NX.

Hence, the correct option is $A$

Suggest Corrections

Similar questions

NX is produced by the following step of reactions M + $X_{2}$ $⟶$ $M X_{2}$ $⟶$ $M X_{2}$ + $X_{2}$ $⟶$ $M_{3} X_{8}$

$M_{3} X_{8}$ + $N_{2} C O_{3}$ $⟶$ NX + $C O_{2}$ + $M_{3} O_{4}$ How much M (metal) is consumed to produce 206 gm of NX. (Take at wt. of M = 56, N = 23, X = 80)

$N X$ is produced by the following step of reactions:

1. $M +$ $X_{2}$ $⟶$ $M X_{2}$

2. $M X_{2}$ + $X_{2}$ $⟶$ $M_{3} X_{8}$

3. $M_{3} X_{8}$ + $N_{2} C O_{3}$ $⟶$ $N X +$ $C O_{2}$ + $M_{3} O_{4}$

How much M (metal) is consumed to produce $206 g$ of $N X$ . (Take atomic weight of $M = 56, N = 23, X = 80$ )

N X

is produced by the following step of reactions:

M + X_{2} ⟶ M X_{2}

3 M X_{2} + X_{2} ⟶ M_{3} X_{8}

M_{3} X_{8} + N_{2} {C O}_{3} ⟶ N X + {C O}_{2} + M_{3} O_{4}

How much

M

(metal) is consumed to produce

206 g m

N X

(Take atomic weight of

M = 56, N = 23, X = 80

)

NX is produced by the following step of reactions M + $X_{2}$ $⟶$ $M X_{2}$ $⟶$ $M X_{2}$ + $X_{2}$ $⟶$ $M_{3} X_{8}$ $M_{3} X_{8}$ + $N_{2} C O_{3}$ $⟶$ NX + $C O_{2}$ + $M_{3} O_{4}$ How much M (metal) is consumed to produce 206 gm of NX. (Take at wt. of M = 56, N = 23, X = 80)

NX is produced by the following step of reactions
$M + X_{2} \to M X_{2}$
$3 M X_{2} + X_{2} \to M_{3} X_{8}$
$M_{3} X_{8} + N_{2} C O_{3} \to N X + C O_{2} + M_{3} O_{4}$
How much metal(M) is consumed to produce 206 g of NX? (at wt of M = 56, N = 23, X = 80)

Join BYJU'S Learning Program

NX is produced by the following set of reactions.M+X2→MX23MX2+X2→M3X8M3X8+Na2CO3→NX+CO2+M3O4How much M (metal) is consumed to produce 206 gm of NX? [Take atomic wt. of M = 56, N = 23, X = 80]

The correct option is D 42 gm 42 gm of M (metal) is consumed to produce 206 gm of NX.Hence, the correct option is A

NX is produced by the following set of reactions.

$M + X_{2} \to M X_{2}$
$3 M X_{2} + X_{2} \to M_{3} X_{8}$
$M_{3} X_{8} + N a_{2} C O_{3} \to N X + C O_{2} + M_{3} O_{4}$
How much M (metal) is consumed to produce 206 gm of NX?
[Take atomic wt. of M = 56, N = 23, X = 80]

The correct option is D $42$ gm
42 gm of M (metal) is consumed to produce 206 gm of NX.

Hence, the correct option is $A$