Nylon $- 5, 10$ can be prepared by:

H_{2} N (C H_{2})_{5} N H_{2} +

Decanoic acid (Sebacic acid)

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H O O C (C H_{2})_{3} C O O H + H_{2} N (C H_{2})_{10} N H_{2}

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H_{2} N (C H_{2})_{6} N H_{2} + H O O C (C H_{2})_{8} C O O H

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H_{2} N (C H_{2})_{10} N H_{2} + H O O C (C H_{2})_{4} C O O H

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Solution

The correct option is A $H_{2} N (C H_{2})_{5} N H_{2} +$ $Decanoic acid (Sebacic acid)$

Nylon - $5, 10$ is made from pentamethylene diamine and sebacic acid as per the reaction shown.

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