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Question

O2 and SO2 gases are filled in ratio of 1:3 by moles in a closed container of 3 L at temperature of 27C. If the partial pressure of O2 is 0.54 atm, then the concentration of SO2 (in mol L1) would be (R=0.082 L atm K1mol1)

A
0.66
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B
0.066
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C
6.6
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D
66
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Solution

The correct option is B 0.066
We have
PO2=χO2×Ptotal0.54=nO2nO2+nSO2×Ptotal
0.54=nO2nO2+3nO2×Ptotal0.54=14×PtotalPtotal=0.54×4=2.16 atmPO2+PSO2=2.16 atmPSO2=2.16PO2=2.160.54=1.62 atm
Concentration of SO2=1.620.082×300=0.066

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