Question

$O_2$ is $16$ times heavier that $H_2$. If at same temperature the $O_2$molecules have average kinetic energy $E$, then at the same temperature the average kinetic energy of $H_2$ molecules will be $\frac{E}{x}$ . Find $x$.

Answer 1

As we know, average kinetic energy,
$E_{avg}=\frac{3}{2}kT$
$E\propto T$
Since temperature is same.
Therefore, average kinetic energy of hydrogen molecule will be same as oxygen molecule
$x=1$
Final answer: (1)