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O2 is 16 time...

Question

$O_{2}$ is $16$ times heavier that $H_{2}$ . If at same temperature the $O_{2}$ molecules have average kinetic energy $E$ , then at the same temperature the average kinetic energy of $H_{2}$ molecules will be $\frac{E}{x}$ . Find $x$ .

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Solution

As we know, average kinetic energy,
$E_{a v g} = \frac{3}{2} k T$
$E \propto T$
Since temperature is same.
Therefore, average kinetic energy of hydrogen molecule will be same as oxygen molecule
$x = 1$
Final answer: (1)

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