Question

$o-Br-C_6{H}_4-{NH}_2$ is :

• A. aliphatic $1^0$ - amine
• B. aromatic $1^0$ - amine
• C. aliphatic $2^0$ - amine
• D. aromatic $2^0$ - amine

Answer 1

The correct option is B aromatic $1^0$ - amine

Since a benzenoid ring is attached directly to the nitrogen atom, it is an aromatic amine.
Also, only 1 hydrogen of ammonia is replaced by alkyl group and there are 2 hydrogens intact. So, it is a $1^0$ amine.

Hence, option $B$ is correct.