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Question

ω is an imaginary cube root of unity . If (1+w2)m=(1+w4)m , then least positive integral value of m is

A
6
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B
5
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C
4
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D
3
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Solution

The correct option is D 3

We have,
(1+w2)m=(1+w4)m ( w3=1)
(1+w2)m=(1+w4)m
(w)m=(w2)m
Looking at the options and solving,
Least positive integral value of m is 3.


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