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Question

O is any point in the interior of ΔABC. then
AB+AC<OB+OC is true /false

A
True
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B
False
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Solution

The correct option is B False

Here, O is any point in the interior of ABC.
E,F points on sides AB and AC.
We know that, the sum of any two sides of triangle is always greater than third.
In ABF
AB+AF>BF
AB+AF>OB+OF ------ ( 1 )
In COF
CF+OF>OC ------ ( 2 )
Adding equations ( 1 ) and ( 2 ) we get,
AB+AF+CF+OF>OB+OF+OC
AB+AF+CF>OB+OC
AB+AC>OB+OC
We can see given statement in question id false.

1498625_1139526_ans_4a30bea488a44845a537a89b4f9e34be.png

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