O is any point inside a rectangle ABCD. then $O B^{2} + O D^{2} = O C^{2} + O A^{2}$
If the above statement is true then mention answer as 1, else mention 0 if false

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Solution

Given, ABCD is a rectangle. O is any point inside the rectangle.
Construction: Construct perpendiculars OP, OQ, OR, OS on each side.
Now, $O A^{2} + O C^{2} = (A S^{2} + O S^{2}) + (O Q^{2} + Q C^{2})$ (Considering right triangles ASO and COQ)
But $A S = B Q$ and $Q C = S D$ , Therefore,
$O A^{2} + O C^{2} = (B Q^{2} + O S^{2}) + (O Q^{2} + S D^{2})$
$O A^{2} + O C^{2} = (B Q^{2} + O Q^{2}) + (O S^{2} + S D^{2})$
$O A^{2} + O C^{2} = O B^{2} + O D^{2}$ (Considering right triangles OSD and OBQ)

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